Ammonia NH3 Gas(nh3)





What is the volume of 8.5g NH3(nh3) gas at S.T.P?
Solution:
The molar mass(M) of NH3=14+3g/mol
Given mass(m)=8.5g
Number of moles(n)=m/M=8.5g/17g/mol=0.5mol
After that
1 mol=22.4L
0.5moL =x
Then by using cross multiplication
x=0.5×22.4L=11.2L
Therefore, the volume of NH3(nh3) occupy at S.T.P is 11.2L
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